When Can 1996 Calendar Be Used Again
| 3. | What was the twenty-four hours of the week on 17th June, 1998? | |||||||
Answer: Selection C Explanation: 17th June, 1998 = (1997 years + Period from i.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = (5 x three) 97 years has 24 spring years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. February. March April May June (31 + 28 + 31 + thirty + 31 + 17) = 168 days Total number of odd days = (0 + 1 + ii + 0) = 3. Given day is Wednesday. |
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168 days = 24 weeks = 0 odd day.| Shruthi said: (Aug 17, 2010) | |
| How to calculate odd days for 300 years? | |
| Bhupendra said: (Aug 18, 2010) | |
| 499*2=899 = no of odd day in leap(for empathize) 1996-499=1497 odd solar day in remaining year (for understand) odd day 899+1497= 2396 total odd day (for understand) 2396/7= 342+ 2/7=> 2odd day (bodily odd day till 1996) 2+ane= three odd day till 1997 (actual odd twenty-four hours till 1997) then 1 Jan 1998= thursday Jan 31 Feb 28 mar 31 april 30 may 31 june 17= wedenesday | |
| Nitesh Nandwana said: (Oct 10, 2010) | |
| @Hi Shruthi,. Information technology is measured that each 100year has v odd days OK ?. (retrieve it ever don't ask why considering this is non our primary problem). So, for 300years 5*3=15 odd days. But 15 days are catechumen-able in weeks. So, 15/7 = ii weeks + 1 odd days. (leave days for calendar week, at present they are not odd). That's why 300years = 1 odd 24-hour interval. | |
| Srinivas said: (Nov iii, 2010) | |
| We tin can caluclate the number of leap years by dividing the given two digit nuber with 4. Supose nosotros will take the to a higher place problem if 98 is divided by the 4 then nosotros will become the no. Of leap years which nix only the multiple of four i.e. 24. Then 97 - 24 = 73. 73 ordinary years and 24 leap years. | |
| Venkatesh said: (Jan xi, 2011) | |
| How did you calculate number of odd days for 97 years?. | |
| Dinesh said: (Jan 11, 2011) | |
| What's odd days in 1600 years = 0 Odd days in 300 years = (5 x 3) 1 97 years has 24 leap years + 73 ordinary years. | |
| Sathi said: (Jan 26, 2011) | |
| How to calculate odd days in a yr ? | |
| Rajesh said: (Feb iv, 2011) | |
| 17th june 1998 year 98+ yr code 24+ calendar month code 05+ day 17+ 144%7 140+four wednesday is the answer | |
| Sandeep said: (Feb 18, 2011) | |
| Mr. Rajesh how yous know year code. | |
| Praveen said: (Feb 19, 2011) | |
| Please tell me how 0 odd days for 400 years ? | |
| Praveen said: (Feb 19, 2011) | |
| If five odd days for 100 years, then for 400 years it volition be 5x4=xx means 20%7 = 6 odd days no...? bit confused about this adding....anybody assistance me please.. | |
| Chetan said: (Mar 3, 2011) | |
| I am not understand trouble correctly. Please anybody explain me. | |
| Vaibhav said: (Mar xvi, 2011) | |
| Nice one rajesh. | |
| Nitin said: (Apr xx, 2011) | |
| How tin I observe no leap year in 97 year. | |
| Aishu said: (Apr 29, 2011) | |
| How to detect the calendar month code rajesh ? | |
| Inshan said: (May 14, 2011) | |
| Think it like this!! Maybe year 0 A.D. is included as an ordinary yr rather than as a jump year. Then, 2000 yrs = 499 spring years. (Year: 0 A.D. is be included.) = 1501 ordinary years But, 1997 yrs = 498 leap yrs = 1499 ordinary years (Yr 1998 is not taken considering it is of this year'due south day of 17th of June that we have to figure out.) ane.) Leap years = 366 days (per yr)/ 7 = Remainder is ii. Therefore, two odd days for every leap yr, i.e. to say, Therefore, full odd days altogether = 2495 days / 7 = 3 odd days. Apr and June, & September and November: xxx days each. Full odd days = 3 + 0 = 3 odd days. | |
| Inshan said: (May 15, 2011) | |
| Sorry for mistake! What I said was that 0 A.D. is non included equally either years! But, I surmise that it is better to take into account every 100 yrs to sympathise such problems better. For this, nosotros demand to effigy out how many ordinary years and leap years are there altogether in a century (100 yrs). If nosotros observe this, we will go to heaven!!! :))) | |
| C.Paththira Selvi said: (May 17, 2011) | |
| How to calculate this sum? | |
| Ranjith said: (Jul vii, 2011) | |
| How could yous tell that 1600 has 0 odd days? | |
| Anupama said: (Jul x, 2011) | |
| Wy we are 300 years and why we are computing odd days for 300 ? | |
| Arya said: (Jul 20, 2011) | |
| Counting of Odd Days: 1 ordinary year = 365 days = (52 weeks + i day.) 1 ordinary twelvemonth has 1 odd day. ane leap year = 366 days = (52 weeks + ii days) 1 bound year has ii odd days. 100 years = 76 ordinary years + 24 jump years = (76 10 1 + 24 ten 2) odd days = 124 odd days. = (17 weeks + days) 5 odd days. Number of odd days in 100 years = 5. Number of odd days in 200 years = (five x 2) iii odd days. Number of odd days in 300 years = (five ten 3) one odd 24-hour interval. Number of odd days in 400 years = (v 10 4 + 1) 0 odd day. | |
| Rinki said: (Jul 25, 2011) | |
| Pls tell me ....why did you lot add 1 in the calculation of odd days in 400 years??? | |
| Vanita said: (Jul 27, 2011) | |
| Number of odd days in 200 years = (five x 2) iii odd days. Number of odd days in 300 years = (5 x 3) 1 odd 24-hour interval. Number of odd days in 400 years = (5 x 4 + 1) 0 odd day. Why, (Number of odd days in 400 years = (5 10 4 + 1) 0 odd day.) in this ane is added , delight clarify | |
| Steffy said: (Aug 22, 2011) | |
| To Nitin: Here nosotros take 97 yrs 97/4=24 leap yrs 97-24=73 ordinary yrs | |
| Ekta said: (Sep 16, 2011) | |
| Thank you Arya. I tin can understand properly your solution. | |
| Sri Harsha. P said: (Sep 17, 2011) | |
| At that place is another way... Remember the code FOR ALL Problems ABOUT CALENDER Calendar month : J F M A G J J A Due south O N D and Lawmaking FOR THE YEAR AT FINAL EX: FOR 17 JUNE 1998 have the last ii numbers in the year for ex. In 1998 accept 98 and divide them by 4 and take merely the quotient and get out the reminder ex: 4)98(24 add the following month code for JUNE 4 ------------ split up the corporeality by 7 i.e., 143/vii ex: 7)143(2 Week S M T Due west T F S IN THE To a higher place Trouble ANSWER IS three So Day IS Westward-Wednesday ANOTHER Example: 15 AUGUST 1947 ADD calendar month code 2 | |
| Raviteja said: (Sep 27, 2011) | |
| For those who did not understand this problem,let me try to explain you lot. The outset affair to be cleared is that for every 400 years at that place are 0 odd days. This is because,in 400 years,there are 97 bound years and 303 ordinary years(remember that 100,200,300 are not leap years but 400 is a leap twelvemonth.Because whatsoever year ending with 00,that year should exist divisible by 400 in order to become a leap year) And so the number of odd days at the end of 400 years will be [(97*2)+(303*1)]=497 days.Convert this into weeks,we get 71weeks + 0odd days=totally 0 odd days Now coming to the trouble, At present coming to the yr 1998, | |
| Janvi said: (Oct 21, 2011) | |
| How you got ordinary days? could you explain? | |
| Hdx said: (November 9, 2011) | |
| Here is complete solution, the year is 1998 16+3=19 Run into from 0 A.D 1600yr+300yr =1900yr We are calling the odd days from the 0 A.D. So 1600 yr has 0 odd days Simply the remaing 300 year has 15 odd days and rest y'all tin can do. | |
| Arun said: (November 12, 2011) | |
| How to calculate odd days for 300 years? I don't understand this only. | |
| Rishi said: (Nov xviii, 2011) | |
| Ishan , Arya and Raviteja Thanks to all u for ur such a caption | |
| Praveen Kumar said: (Nov 22, 2011) | |
| How we gat an idea to accept 1600 years and 300 years in above problem. | |
| Muthaiyan said: (Dec 27, 2011) | |
| Step 1:[1997+one.1.1998to17.half-dozen.1998] step2: 1997=1600+300+97=> 1600 is 0 odd days, 300 is 1 odd twenty-four hours step3: summate 97 step4:97/four= 24,=> [24-97=73] step5:24leap twelvemonth +73 ordinary year=>(24*2)+(73*ane)=127 step6:127/7=17,=>17week+2 odd days step7:1998 is an ordinary year therefore [31+28+31+30+31+17=168] ste8:168/7=24weeks+0 odd days step9:add together all odd days nosotros get 3 is an wednesday | |
| Ravihans said: (Jan x, 2012) | |
| Good explanation rajesh. | |
| Saurabh said: (February 3, 2012) | |
| Muthaiyan good manner of explanation. | |
| Chitaranjan said: (Mar 7, 2012) | |
| 1998=1600+300+98 1600-->0 odd days 300-->ane odd mean solar day 98 years= 24 leap yr +73 normal year = 24*two+73*1=121 odd =121/seven=2odd Jan to June 17 =168 days =168/7= 0 odds | |
| Mickey said: (April xvi, 2012) | |
| A simple trick to solve calender problems for those who don't wana go for tidious concepts. Just memorize these codes for months. Jan=1. Days:. S=one. Formula = day + calendar month no. + (x-1900) + (ten-1900) /four. Eg. 17 june 1998. Req solar day = 17+5+ (1998-1900) + (1998-1900) /four. At present. Devide 144 by seven. This is the simplest trick. We merely have to memorize the codes for months. | |
| Ravi said: (May 8, 2012) | |
| Give thanks you harsha But tell me in case of whatsoever instance if date is of 16 jan 2002. becoz here we will divide 02 by iv which gives 0. thn code for jan =0, year code =half-dozen, adding 02+sixteen=18. Hence total gives=0(quotient)+0(calendar month lawmaking)+6(year code)+eighteen(addition of last ii digits and date)=24 24/seven gives quotient gives remainder as three i.e tuesday. just on this date it is saturday... plz explain.. | |
| Sruthi said: (May 26, 2012) | |
| How to know how many odd days to 121 days? | |
| Shail said: (Aug 19, 2012) | |
| Hi every i, Hither is the best solution for this for Arun and all those who want to know well-nigh concepts of using 1600 and and so 300 years. Basics : at present for a twelvemonth we take total of 365 day . Step1: every ordinary year(365 days)=1 odd Footstep 5: for 300 years odd days= v+5+v=15:: i odd Stride seven: Rest is explained conspicuously. | |
| Radhika said: (Sep 2, 2012) | |
| How do nosotros calculate for 75years it is 18 leap years +57 ordinary years ? | |
| Roxy said: (December 5, 2012) | |
| 17 June 2000. What is the day, can any 1 explicate the solution. Please calculate using odd days method? The answer is Sabbatum. | |
| Ramya said: (Dec 9, 2012) | |
| How to calculate no.of bound years in given years? Ex. 87 years. | |
| Shilpa said: (Dec 11, 2012) | |
| How many odd days are there in 500 years? | |
| Vicky said: (Dec 31, 2012) | |
| Leap year comes for every four years The basic rule to know virtually leap year is that the yr should be divisible by 4 For Eg: iv, 8, 12, 16, twenty................100, 104 etc., And then hither as per my knowldeged 25 spring years should exists for every 100 years. why all are considering 24yrs in 100 years? Need clarity on this. | |
| Juhi said: (Jul xv, 2013) | |
| Co-ordinate to my thinking: 97 years has 23 leap years not 24 Then in this example from 1901 to 2000 the last one is leap is 2000, which we are non counting because we want to count from 1901 to 1997. So delight justify your respond. | |
| Keya said: (Jul 19, 2013) | |
| @Juhi. The centuries divisible by 400, like 400, 800, 1200, 1600, 2000...etc take 25 leap year and 75 ordinary years. In given question we have to calculate from 1900 to 1997 therefore. 1998 - ordinary twelvemonth. So from 1901 to 1997 - ordinary years will be = 75-ii = 73. And leap year will be = 25-1 = 24. | |
| Priya Singh said: (Sep 21, 2013) | |
| 300 years v*three = fifteen odd days. What is 5 and 3. Delight tell me ? | |
| Abhi said: (Oct ane, 2013) | |
| Guys, Could assistance me, what would be the 24-hour interval on 13th-july-1992 ? Need answer with procedure. Please? | |
| Goms said: (Oct fourteen, 2013) | |
| The basic rule to know well-nigh bound year is that the year should be divisible by 4. For Eg: 4, 8, 12, 16, 20................100, 104 etc., Then here as per my knowledged 25 leap years should exists for every 100 years. why all are considering 24 yrs in 100 years? | |
| Vikram said: (Nov 29, 2013) | |
| Month codes: January- one, Feb- four, Mar- iv, Apr- 0, May- 2, June- 5. July- 0, Aug- iii, Sep- vi, Oct- 1, Nov- 4, Dec- 6. Twelvemonth codes: 1500-99: 0 Day codes: Sat- 0, Sun- 1, Mon- 2, Tue- iii, Wednesday- 4, Thu- five, Fri- six. Here, 17+05+98+24+00 = 144. 144/7 = twenty+ 4 days. Which is wednesday | |
| Ravi said: (Dec 12, 2013) | |
| Why you lot taken 300 years ? why not 400 years delight explain in detail. | |
| Naresh said: (Dec 17, 2013) | |
| Hi Everyone. The uncomplicated answer is: 1996+two = 1996(leap twelvemonth)+1 ordinary twelvemonth+Jan to june 17th. i.e Wed. | |
| Vishnu said: (Jan 1, 2014) | |
| The question is what is day of 17 june 1998? If the year is 1998 that is mean in 100 year gets total 25 leap years if getting 25 leap in 100 year so why using 24 leap yr in in a higher place comments. Calculating jump twelvemonth. Computing odd days in jan = 31 days Dividing by 7 to 168 days (7 hateful 7 days in week). 168/7= 24 = 24 weeks + 0 odd days (there is any more days). If eg., 170 /7 = 24 weeks + 2 odd days. Only this not understood. In above talk over why used 1900, 300, 400. If the year is 1998. We should have have in 1998 years. 1901 to 2000 years = total 100 years. 1901 to 1997 years = 97 years. 24 bound twelvemonth + 52 weeks + ane odd days. | |
| Gayatri said: (Jan 27, 2014) | |
| Nosotros can summate the twenty-four hour period of week based on electric current engagement and day. Whenever we got dorsum one yr on the same date the day of week volition be ane less than today's day of week. For case today is 27th january 2014 Mon means 27th january 2013 was one day backside of Monday i.e Sunday. If the year is leap year the twenty-four hour period of calendar week goes back two days for examples if 27th january 2013 is Sunday and the previous twelvemonth 2012 is leap twelvemonth so 27th jan 2012 will be ii twenty-four hours behind sunday i.east friday. If like this nosotros summate we accept : 27th january 2013 - Sunday. SO now 27th Jan 1998 was tuesday. Jan Feb Mar Apr May june Now total = 142 days betwixt 27th jan 1998(Tuesday) and 17th june 1998 . To calculate the twenty-four hours carve up full no of days by 7 and bank check the remainder. If remainder is 0 information technology would exist previous solar day of calendar week. If residue is ane information technology would be aforementioned day of week. If remainder 2 it would be next day of week so on. And so here 142/7 = 20 and remainder 2 so the day of week would exist Wednesday(Adjacent day of Tuesday). | |
| Gayatri said: (Jan 27, 2014) | |
| Apply doomsday algorithm : Think that last mean solar day of feb , 4th april, sixth july , 8th august , 10th october and 12th december will have the same mean solar day of week which is known as doomsday and we demand to summate it in the following way : For 1900-1999 ever accept the anchor day as midweek. So now formula for calculating the doomsday: Doomsday = anchor(wed for 1900-99 tue for 2000-2099) + Y/12(ignore decimal) + remainder(Y/12) + {remainder(Y/12)/4}. Accept just final two digits of the Year. Based on the formula we accept for 17th june 1998 we have: Doomsday = wednesday + 98/12 + Remainder(98/12) + Rest(98/12)/4. Wednesday + 8 + 2 + 2/4. So from the above listing mentioned for the nearest doomsday we tin can come across that 6th june is the nearest doomsday. So 6th june will have the day Saturday. 17th june - midweek. | |
| Avishek said: (Feb 17, 2014) | |
| Number of odd days in 97 years (24 ten 2 + 73) = 121 = 2 odd days. Tin't understand this part. Can anybody explain me this part ? | |
| Riya said: (Feb 25, 2014) | |
| How we got 24 bound year in 100 year. It should be 100/4 = 25. Why not 25? but 24. | |
| Ritesh said: (Apr 17, 2014) | |
| Why 400 years have 0 odd day? | |
| Narayan Das said: (May sixteen, 2014) | |
| To notice out any day of any year of date we have to get through a formula. Always call back Lawmaking: January Feb Mar Apr May June July Aug Sep Oct Nov Dec So now today is 17/05/2014 is Saturday.(today'south date) At present leap year(the twelvemonth which is divisible by 4 or 400) coming between 1998 and 2014 is 2000,2004,2018,2012 means four. And year gap between 1998 to 2014 is xvi. Now add xvi to iv and then divide with 7(days in a week) So if today is Saturday then 17/05/1998 will be Saturday - 6 = Sunday.(since we are coming to dorsum year and so we should differentiate) Now carve up vii in 31, result is 3 So if 17/05/1998 is Sunday then 17/06/1998 will exist Sun + 3= Wed.(Since we are going frontwards yr we should add) | |
| Harish said: (Jun 26, 2014) | |
| Solution: First we calculate upto 1997. For 1600 0odd days because 1600 is divisible past iv so information technology is 0. While dividing 121 by 7 nosotros get residue every bit 2 that is ii odd days. Dominicus Mon Tue Wednesday Thu Fri Sat | |
| Dharsinipriya said: (Jul 18, 2014) | |
| How to summate jump twelvemonth and ordinary year between 200 years? | |
| Pragati said: (Jul 26, 2014) | |
| Get-go divide that no by 4. 200/4 = fifty is the spring year. And 200-50 = 150 is the ordinary year. | |
| Vinod Zala said: (Aug xiv, 2014) | |
| Friends it's and so simple, Recollect just code: Year Lawmaking: 1600-1699 = 6. Month Lawmaking: January = 0 Day Code: Sun = 0 Steps to solve: What was mean solar day on 17/8/1998 ? Stride:1 (add day + last ii digit of years). (17+98=115). Footstep:2 (split up last two digit of years by 4). 98/four == 24. Stride:3 (add code value) 115 Footstep: 4 (divide result footstep iii by vii). 143/7 = 3. Stride:5 (lucifer with 24-hour interval code). 3 === Wednesday. | |
| Sahithi said: (Sep xv, 2014) | |
| Please whatever one explain how to observe 11th october 1993 - day? But above explained rules are not giving exact day what it is. | |
| Deepak said: (Sep 17, 2014) | |
| How to calculate odd twenty-four hours in 1600 years? | |
| Maheshmydo said: (Oct 17, 2014) | |
| How did you make it at MONTH CODES? | |
| Prince said: (Dec 18, 2014) | |
| Nosotros tin solve this problem past going back from 2000 to 17 June 1998. = 2000-two odd days (spring year). = 1999-one odd day. = 1988 (197 days i.east 1 odd 24-hour interval) (31 dec+thirty nov. 17 june). Total 4 odd days. Since nosotros have reversely calculated information technology. Sat, Fri, Thurs, Midweek. | |
| John said: (January 9, 2015) | |
| @Mickey. Now divide 144 by seven. We'll get quotient = twenty and balance = iv. So 4th day is Wednesday. Here rest is wrong. We will get information technology as 5. How you go remainder as 4? | |
| Monu said: (Feb iii, 2015) | |
| If 15 august 1993 is Friday then what would exist the day of 6th march of aforementioned year? Everyone delight answer this. | |
| Kavya said: (Feb 21, 2015) | |
| Is in that location any shortcut? Its very complicated, confusing, odd days, why in that location is a demand to take 1600, 400, it volition take more fourth dimension in competitive exams. Please tell easy way to solve if have. | |
| Mamta said: (Jun 23, 2015) | |
| Can anybody explain me? I can't understand. | |
| Prateek said: (Jul 9, 2015) | |
| How come 100 years have 76 ordinary and 24 lap years ? And how it is calculated for any number of years? | |
| Saikumar said: (Jul 12, 2015) | |
| Formula = (Appointment+No of normal yr+No of leap year+Calendar month code+Century lawmaking)/7. (17+98+24+4+0)/seven = 143/7. And remainder is 3 code of week is Midweek. | |
| Santhosh said: (Aug two, 2015) | |
| How to summate number of odd days for 2008, 2009, 2010? | |
| Surya said: (Aug 10, 2015) | |
| I tin can sympathize that problem. Then please explain simple to way? | |
| Surya said: (Aug ten, 2015) | |
| I cannot sympathize our calculation so delight say simple way. | |
| Ravi said: (Aug thirteen, 2015) | |
| Hey dude, its but easy. 97/4 gives 24 and remaining 3. And so, 76-3=73. So 97 =73 ordinary year and 24 spring year. | |
| Khan said: (Aug 22, 2015) | |
| Only why we are computing odd days of 300? And what the role of it? Please make me empathize. | |
| Suraj Singh said: (Sep two, 2015) | |
| Before asking questions, yous guys should have articulate concept on bound year. A spring year is a year, which is divisible past 400, or which is divisible past four and non divisible by 100. And then 100, 200, 300 is not a bound year. So in 100 years, only 24 leap years, and and so on. | |
| Saurabh said: (Sep 4, 2015) | |
| 1998 was the jump yr then the February month of 1998 has 1 odd day? | |
| Likitha said: (Sep 20, 2015) | |
| Why should nosotros consider 1600 and 300 years of odd days here? | |
| Yatindra Umrane said: (Sep 29, 2015) | |
| What is odd days in 1600 years = 0 and odd days in 300 years = (5 x iii)1? Why we calculate 1600 years and 300 years? | |
| Gurasheesh Singh said: (Oct 8, 2015) | |
| What are the number of odd days in 99 years? | |
| Krocy said: (Nov 1, 2015) | |
| 3 odd days = Midweek. | |
| Gyanendra Vaishya said: (Nov ane, 2015) | |
| Q. How to detect number of odd days in 300 years? Solution: First number of odd days in 100 years = 98 ordinary years + 2 leap years (2 spring years means: ii*2 = iv odd days). 1+4 = 5 odd days. 100 years had 5 odd days. 300 years had = five odd days*3. = xv odd days = 7*ii +i. = 0+one (seven days = 0 odd days so, 7+seven= 0+0 = 0 odd days = days). = i odd days. | |
| Deepika said: (Dec 18, 2015) | |
| How tin nosotros calculate in a 100 years in that location are 76 ordinary years and 24 spring years? | |
| Raju said: (Jan 18, 2016) | |
| How tin summate in a calendar week? | |
| Asif Syed said: (Mar ii, 2016) | |
| How tin we calculate in a 100 years at that place are 76 ordinary years and 24 leap years? 100/4 = 25; and so we should have 25 spring years, but why 24 please anyone clarify this. | |
| Rajesh said: (Mar 27, 2016) | |
| Is there is any shortcut mode and uncomplicated way to resolve the to a higher place query? | |
| Madhukumar K Southward said: (Mar 29, 2016) | |
| Today is 29th March 2016, Tuesday. But if I calculate every bit your procedure, I'g getting Wednesday every bit the answer. Because 2016 is a bound year, should count Feb as 29 days. Please clarify. | |
| Sathesh said: (Apr 19, 2016) | |
| 100 years are non coming Tuesday or Thursday or Sat. | |
| Pratik Chudasama said: (May 20, 2016) | |
| The reply should be Tuesday. Please cheque information technology over again. | |
| Akshay said: (Jun 28, 2016) | |
| Aye. The answer should be Tuesday. Considering in 100 years there are 24 leap years. Just in 97 years there are 23 spring years. I think so. Where I m incorrect tell me, delight. | |
| Akshay said: (Jun 28, 2016) | |
| @Deepika and @Asif, Just listen. 100/four = 25, but the first yr is not divisible by 4. (notation that) For instance from 2001 to 2100 ....... 2001 is not leap year. That's why 25 - 1 = 24 jump years in 100 years. | |
| Krishnoshakawat said: (Jul seven, 2016) | |
| Why will nosotros calculate from 1600? Everyone, please assist me. | |
| Vissu said: (Jul 7, 2016) | |
| Please explain everything ones how has come to Wednesday. | |
| Karan said: (Jul 15, 2016) | |
| Tin y'all help me in calculating? How many odd days in fifty years? Demand information technology asap! | |
| Srimant said: (Jul 15, 2016) | |
| How month code comes like; J0, F3, M3, A6, -----, O0, N3, D5? | |
| Bidhya said: (Jul 22, 2016) | |
| What is odd twenty-four hours? I don't understand to find this. | |
| Priyanka Agrawal said: (Jul 30, 2016) | |
| @ Bidhya. When no.of days are divided by 7 we get reminder, the reminder is called odd days. Eg. In one year [non-leap year] in that location are 365 days, So 365/vii = 1[reminder]. And so there is 1 Odd day in 1 yr. Merely no.of days/seven = reminder means odd days. | |
| Vidya said: (Aug 13, 2016) | |
| Please explain calculation 76 ordinary years in 100 years, because I got it as 75 ordinary years. | |
| Shyni said: (Aug 26, 2016) | |
| How to calculate the number of odd days in 300 years? | |
| Sonali said: (Aug thirty, 2016) | |
| How did you know that Feb has 28 days regarding to a higher place instance? | |
| Sathiyaraj said: (Sep 5, 2016) | |
| 1998/4 = 499 leap years + 2 days, 499/7 = 71 weeks + 2 days, And then, 01-01-1998 falls on Wednesday(fourth twenty-four hour period of calendar week), January 31 + Feb 28 + Mar 31 + Apr 30 + May 31 + Jun 17 = 168 /7 = 24 weeks + 0 solar day, And so, 17 jun 1998 falls on Wednesday. | |
| Sreejith S Due south said: (Sep 21, 2016) | |
| Read important formula of calendar problem, that time yous will exist realized. | |
| Mohit said: (Oct xi, 2016) | |
| @ Sri Harsha. Can you apply that trick on example Similar 2002, 2014? | |
| Karthik Babu said: (Oct 31, 2016) | |
| Information technology should be 23 jump years know because 2000 is besides leap year. | |
| Khushi said: (Nov half-dozen, 2016) | |
| Why we are considering odd days for 300 years? Can nosotros consider 400 year instead of 300 year than odd days also changes. | |
| Manoj Kumar Majhi said: (Jan 3, 2017) | |
| Find out the day in the date of 25 .5.1975. | |
| Sayali said: (Jan v, 2017) | |
| @Vikram. How did you lot find calendar month codes? | |
| Ekowseegar said: (Jan x, 2017) | |
| How do detect the odd days in 1999? | |
| Akash Anand said: (Jan 22, 2017) | |
| The answer should be Thursday non Wed because in that location are iii odd days. If at that place had been ii odd days then respond would take been Wednesday. | |
| Ramya said: (Feb 5, 2017) | |
| @Ekowseegar. 1999 tin can exist written as 1600+300+99. Actress days=(24 * 2 + 75) Odd days in 123 is the reminder of 123/7 that is 4. Therefore total no of odd days = 0 + 1 + four = 5. | |
| Kavitha said: (Feb 25, 2017) | |
| How 1600 and 300 come? Delight requite me the proffer to solve information technology. | |
| Abhi said: (May nine, 2017) | |
| One other way of Finding the Answer is : Merely remember that 1st Jan 2000 was Saturday. 1999 (not spring twelvemonth so 365 days) = 52 weeks + 1 day. | |
| Gardas Anusha said: (May 18, 2017) | |
| In 100 years isn't this correct: 25 leap years + 75 ordinary years? 4*i=4 .. iv*two=eight.. 4*3=12.. ......... 4*25=100 and so 25 leap years. | |
| Hemant said: (Jul 17, 2017) | |
| Sir, how yous ended 2 odd days from 121? Delight explicate me. | |
| Nitin Gupta said: (Aug xv, 2017) | |
| Anyone explain why 144025036146 is the codes for month explain how one arrives for January for ordinary year and 4 for feb again four for March I know 31/7=3 is code for feb bound twelvemonth but why 144 for jan feb march. | |
| Kunal More said: (Nov 1, 2017) | |
| How to calculate leap year in 100 years? | |
| Zemanian said: (Dec 15, 2017) | |
| In that location's a better way to solve this: Nosotros know that for 2000 years, the number of odd days is 0. for the previous 2000 years, in that location are 0 odd days. which means in that location are 0 odd days. now the twenty-four hours of the calendar week for 17 June 2001 is Sunday. at present nosotros need the mean solar day for 17 June 1998. Simply subtract the odd days of the preceding three years. 2000 is a leap year, whereas 1999 and 1998 are ordinary years. So 0 - 2 - ane - 1 = -iv. Go back iv days from Sunday and y'all go Wed. | |
| Ayesha said: (Dec 26, 2017) | |
| Why it's needed to calculate odd days for 1600 and 300? | |
| Anuradha said: (Feb 15, 2018) | |
| How to calculate ordinary twelvemonth and leap years in one century? Please explain? | |
| Joy said: (Apr 22, 2018) | |
| Simple , bound year = 100 / iv = 25. Ordinary year = 100 - 25 = 75. | |
| Savanth said: (May 2, 2018) | |
| If yous want to find number of odd days in 100 years, then 100/4=25.(But. Quotient) Now,( 100 +25)/7=6(remainder). So, there are 6 odd days in 100 no of Years. | |
| Pratit said: (May 24, 2018) | |
| How many odd days in betwixt 1901 to 2000? Please tell me the answer with the explanation. | |
| Deepak Padmule said: (Jun 28, 2018) | |
| In 1998. i.due east, 98 is a bound year and then y'all should have to consider 29 days in Feb month but yous hadn't considered information technology. | |
| Bharathi said: (Jul 21, 2018) | |
| Can anybody derive and say 15th June 1998 is what mean solar day? Please | |
| Shreya said: (Jul 22, 2018) | |
| How to calculate 1 odd 24-hour interval in 300years? | |
| Roja St said: (Jul 31, 2018) | |
| Cheers @Sri Harsha. | |
| Akshatha said: (Sep 26, 2018) | |
| Thanks for your answer @Sri Harsha. | |
| Sreeja said: (Sep 26, 2018) | |
| Why should we take 1600 and 300 here? Please explain. | |
| Suhel said: (Nov 1, 2018) | |
| @Rajesh. Tin can you please explain how get the yr code. | |
| Akshakumar said: (February 21, 2019) | |
| 1600 + 300 + 97 + (J to March)+17. 0 + one + {24(leap yr)+73(ordinary y)}+(3+0+3+two+three) + 17. | |
| Prabhu said: (May 7, 2019) | |
| Take 1996 is a spring yera so it has 2 odd days. Then 1997 has 1 odd solar day and then full odd twenty-four hour period till 1997 is; Then, | |
| Mim said: (Jun 1, 2019) | |
| @Akshay. 1st year to 10th year= ii Bound yr(LY) + 8 ordinary year(OY) In total 25 spring twelvemonth and 75 ordinary years in 100 years. Here we don't count 1st year as leap year. We've counted 1st year as OY. Then how 24 LY + 76 OY in 100 yr? Please explain to me. | |
| R G said: (Jul i, 2019) | |
| Hither, for calculation of 1997, they have said 1600 yrs + 300 yrs. So the odd twenty-four hours obtained is 1. But instead, if we practise 1700 yrs + 200 yrs than odd days obtained will exist different. How to understand this? Please explicate to me. | |
| Ashok said: (Jul 6, 2019) | |
| @All. Kickoff nosotros need to know nearly century codes; Then we need to know month codes. jan =0,feb=3, mar=3, apr=half-dozen, may=one, jun=iv, july=6, aug=2, spt=five, oct=0, nvm=3, dec=5 afterv knowing this.. After, ADD ALL THE VALUES WE Go 42 SINCE We Have vii DAYS Carve up THE NUMBER 42/7=0. | |
| Shruthi said: (Aug six, 2019) | |
| How we got 5*iii? Please tell me. | |
| Suchitra said: (Sep 15, 2019) | |
| Thank you for the clear explanation @Prabhu. | |
| Sharath said: (Sep 21, 2019) | |
| 400 years = (five 10 four + one). Here 1 is added because of leap twelvemonth ! | |
| Yashu said: (Sep 26, 2019) | |
| Anyone tell why we consider 300 & 1600 years merely. Why don't we consider 400 or other than that? | |
| Shweta said: (October i, 2019) | |
| Thank you @Arya, @Inshan, @Nitesh. | |
| Kirtan said: (Oct 13, 2019) | |
| How many bound years are in that location between1701 and 1900 (both included) ? | |
| Dream Boy said: (November vi, 2019) | |
| How to know a twenty-four hours of a item appointment? | |
| Dream Male child said: (November 6, 2019) | |
| How to know a mean solar day of a detail date? | |
| Kavi said: (Nov 28, 2019) | |
| Which twenty-four hours of 21 July 1997. Draw below. | |
| Sound said: (Jan 24, 2020) | |
| Why do we take that 1600 and 300? | |
| Binudass said: (February iii, 2020) | |
| How can I calculate the no of odd days in 100 years? Delight, anyone, tell me. | |
| Shagun Pachisia said: (Jun 23, 2020) | |
| How we calculate no of leap years in 97 years? Delight explain me. | |
| Jala said: (Jul 2, 2020) | |
| 98 is a leap twelvemonth then Feb has 29 days right? | |
| Shikare said: (Aug 16, 2020) | |
| Why nosotros took 300 years? | |
| Suba said: (February nine, 2021) | |
| Could anyone explain me why are we considering 300 years? . | |
| Pratyush Singh said: (Jun 12, 2021) | |
| 96/4 = 24. and 96 -24 =72 ordinary years. This means in 96 years there are 24 leap years and 72 ordinary years. Then, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary). i.e. 97-24 = 73 ordinary years. | |
| Aman said: (Aug 10, 2021) | |
| Hello, I don't understand about 1600 and 300 years, delight explicate. | |
| Ananthu Sv said: (Aug 26, 2021) | |
| @All. Just remember; 100yrs --> 5 odd 1600 because it gives odd days as 0 considering its a multiple of 400. For 97yrs -> 24 jump year and 73 ordinary years. And then,24 * 2 + 73*1 = 121. Therefore; Jan i to jun17 -> we have 3 (31 days), 1 (thirty twenty-four hours), 1 (28 day), and 17 days. Remember: So, we get three * three + 1 * 2 + i * 0 + 17 = ix+2+17 = 28 odd days. For final stride: Chart: So three in the nautical chart is *WEDNESDAY*. | |
| Vani Arora said: (February 10, 2022) | |
| I cannot get the answer. Anyone help me to get the answer clearly. | |
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